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5s^2+s-4=0
a = 5; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·5·(-4)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-9}{2*5}=\frac{-10}{10} =-1 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+9}{2*5}=\frac{8}{10} =4/5 $
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